0.05 mol dm-3 HCl is neutralized by 25 cm3 NaOH. If the volume of acid used is 32.00cm3, what is the concentration of the base
- 0.016 mol dm-3
- 0.032 mol dm-3
- 0.039 mol dm-3
-
0.064 mol dm-3
The correct answer is: D
Explanation
HCl + NaOH → NaCl + H2O
CAVA = NA/NB = (0.05 * 32)/(CB * 25)
∴ CB = (0.05 * 32)/25 = 0.064 mol dm-3
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