In recharging a lead-acid accumulator, the reaction at the cathode can be represented as
- Pb2+(aq) + SO2-4(aq) →PbSO4(s)
-
Pb2+(aq) + 2e- →Pb(s)
- Pb2+(aq) + 2H2O(l) → PbO2(s) + 4H+(aq) + 4e-
- Pb(s) → Pb2+(aq) + 2e-
The correct answer is: B
Explanation
In lead acid ,lead dissociates at the cathode Pb2+(aq) + 2e- →Pb(s)
There is an explanation video available .