CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g)
What is the effect of increasing the pressure on the equilibrium reaction above?
- The equilibrium is shifted to the left
- The equilibrium is shifted to the right
-
There is no effect
- More H2(g) is produced
The correct answer is: C
Explanation
When amount / volume of gaseous reactants equal amount / volume of gaseous products, the change in pressure has no effect on the equilibrium position.
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