Calculate the percentage by mass of nitrogen in calcium trioxonitrate (V)
[Ca = 40, N = 14, O = 16]
- 8.5%
- 13.1%
-
17.1%
- 27.6%
The correct answer is: C
Explanation
Calcium trioxonitrate(V) is (CaNO3)2
The molecular mass of Ca(NO3)2 = 40 + (14 + (16 X 3)) x 2 = 164
Relative molecular mass of nitrogen(N) = 14 x 2 = 28
% by mass of nitrogen in Ca(NO3)2 = \(\frac{28}{164} x \(\frac{100}{1}
= 17.073 ≈ 17.1
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