Calculate the solubility in mol dm-3 of 40g of CuSO4 dissolved in 100g of water at 120°C?
[Cu = 64, S = 32, O = 16]
- 4.00
-
2.50
- 0.40
- 0.25
The correct answer is: B
Explanation
Solubility = \(\frac{\text{number of moles of solution}}{\text{vol of solution}}\)
100g of water = 100 cm\(^3\) = 0.1 dm\(^3\).
CuSO\(_4\) = 160 g/mol
No of moles of CuSO\(_4\) in 40g = \(\frac{40}{160}\)
= 0.25 mol.
Solubility = \(\frac{0.25}{0.1}\)
= 2.5 moldm\(^{-3}\).
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