\(Na_2O_{2(s)} + H_2O_{(1)}\)→ \(NaOH_{(s)} +O_{2(g)}\)
The substance that is oxidized in the reaction above is
- \(Na_2O_{2(s)}\)
- NaOH(aq)
-
H2O(1)
- O2(g)
The correct answer is: C
Explanation
\(Na_2O_2\) removes hydrogen from water and oxidizes it to free non-metallic oxygen.
There is an explanation video available .