If the change in free energy of a system is -899 Jmol-1 and the entropy change is 10Jmol-1k-1 at 250C, calculate the enthalpy change.
-
+2081 Jmol-1
- -2081 Jmol-1
- -649 Jmol-1
- +649 Jmol-1
The correct answer is: A
Explanation
∆G = ∆H - T∆S-899 = ∆H - 2980
∆H = -899 + 2980 = + 2081 Jmol-1
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