A hydrocarbon has an empirical formula CH and a vapour density of 39. Determine its molecular formula.
[C = 12, H = 1]
- C2H6
- C3H8
- C3H4
-
C6H6
The correct answer is: D
Explanation
molecular mass = 2 x vapour density= 2 x 39 = 79
∴ Cn Hn = 78
12n + 1n = 78
13n = 78
n = \(\frac{78}{13}\) = 6
∴ Cn Hn = C 6H 6