\(Cu_2S_{(s)}+ O_{2(g)} = 2CU_{(s)} + SO_{2(g)}\).
In the above reaction, the oxidation number of Cu changes from ___ to _______?
-
+1 to 0
- 0 to +2
- +2 to +1
- 0 to +1
The correct answer is: A
Explanation
The oxidation number is from +1 to O as a result of the release of sulphur. Options B, C, and D are not the actual oxidation number for copper
There is an explanation video available .