An oxidation state of Cr in K2Cr2O7
- 7
-
6
- 5
- 4
The correct answer is: B
Explanation
The oxidation state of K2Cr2O7 is +6. option A,C,D are the oxidation state of other elements like O7,C14, etc.
\(+2 + 2x + (-2\times7) =0\)
\(2x=12\)
\(x = +6\)
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