In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is
- 4H+ 4e - 2H2
-
4OH= 4e- + 2H2O + O2
- 2OH - 2e- = 2OH
- 2OH- + 2OH = 2H2O + O2
The correct answer is: B
Explanation
40H − 4e → 2H2O + O2is the reaction of sun at the anode in the electrolysis of CuSO4 (g) using platinum particles. Option A,C,D are not formed as a result of the equation
There is an explanation video available .