Calculate the volume in cm3 of oxygen evolved at s.t.p when a current of 5A is passed through acidified water for 193s?
[F = 96500 C mol1. Molar volume of a gas at s.t.p = 22.4dm3]
-
0.056dm3
- 0.224dm3
- 224.000dm3
- 56.000dm3
The correct answer is: A
Explanation
Q = 193 x 5 = 965C40H \(\mapsto\) 2H2O + O2 + 4e
4 x 96500C = 22.4dm3
965C = x
x = \(\frac{22.4 \times 965}{4 \times 96500}\)
= 0.056dm3
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