A given mass of gas occupies 2dm3 at 300k. At what temperature will its volume be doubled, keeping the pressure constant?
- 400k
- 480k
- 550k
-
600k
The correct answer is: D
Explanation
At constant pressure connotes Charle's law\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)
\(\frac{2dm^3}{300k}\) = 2 x \(\frac{2dm^3}{T_2}\)
T2= 600k
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