Cu2S(g) + O2(g) → 2Cu + SO2(g)
What is the change in the oxidation number of copper in the reaction?
- 0 to + 2
- 0 to + 1
-
+ 1 to 0
- + 2 to + 1
The correct answer is: C
Explanation
In the reactant;
Cu2S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O
The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
There is an explanation video available .