Calculate the amount in moles of a gas which occupies 10.5 dm3 at 6 atm and 30oC [R = 0.082 atm dm3 K-1 mol-1]
-
2.536
- 1.623
- 4.736
- 0.394
The correct answer is: A
Explanation
For an ideal gas PV = nRT
Amount in moles = n
Volume v = 10.5dm3
Pressure P = 6atm
Temperature T = 30°C + 273 = 303k
R, Gas constant = 0.082 atmdm3k-1 mol
Recall from ideal gas equation
pv = nRT
n = \(\frac{RV}{RT}\)
n = \(\frac{6 \times 10.5}{0.082 \times 303}\)
n= 2.536mol
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