To what volume must 300cm\(^3\) of 0.60M sodium hydroxide solution be diluted to give a 0.40M solution?
-
450cm\(^3\)
- 300cm\(^3\)
- 200cm\(^3\)
- 150cm\(^3\)
The correct answer is: A
Explanation
From the dilution law
C\(_1\)V\(_1\) = C\(_2\)V\(_2\)
C\(_1\) = Initial Concentration of NaOH = 0.6M
V\(_1\) = Initial Volume of NaOH = 300cm3
C\(_2\) = Final Concentration of NaOH = 0.4M
V\(_2\) = Final Volume of NaOH = ?
V\(_2\) = \(\frac{C_1V_1}{C_2}\)
V\(_2\) = \(\frac{0.6 \times 300}{0.4}\)
V\(_2\) = 450 cm\(^3\)
Correct Computation as it follows the equation specified
There is an explanation video available .