The hydrogen ion concentration of a sample of orange juice is 2.0 X 10\(^{-11}\)moldm\(^{-3}\). What is its p\(^{OH}\)? [log102 = 0.3010]
-
3.30
- 13.00
- 10.70
- 11.30
The correct answer is: A
Explanation
PH+POH=14
p\(^{H}\) = Log [H\(^+\)]
p[H\(^+\) ] = 2.0 X 10\(^{-11}\)moldm\(^{-3}\)
p\(^{H}\) = Log [2.0 X 10\(^{-11}\)]
p\(^{H}\) = 10.70
10.70+ p\(^{OH}\) =14
p\(^{OH}\) = 14 -10.70
= 3.30
There is an explanation video available .