Consider the reaction
A\(_{(s)}\) + 2B\(_{(g)}\) → 2C\(_{(aq)}\) + D\(_{(g)}\)
What will be the effect of a decrease in pressure on the reaction?
- the equilibrium will shift
- rate of forward reaction will increase
-
rate of backward reaction will increase
- rates of forward and backward reaction are not affected
The correct answer is: C
Explanation
Given: The equation below
A\(_{(s)}\) + 2B\(_{(g)}\) → 2C\(_{(aq)}\) + D\(_{(g)}\)
According to Le Chatelier's Principle:
Pressure changes affects only the gaseous reactants and products
There must be different amount of gaseous particles on both sides.
Generally; a decrease in the pressure shifts the equilibrium position in favor of the side with larger volume of gases.
I.e rates of backward reaction.
NB: This is a correction to the video explanation.
There is an explanation video available .