At 27°C, 58.5g of sodium chloride is present in 250cm\(^3\) of a solution. The solubility of sodium chloride at this temperature is?
(molar mass of sodium chloride = 111.0gmol\(^{-1}\))
-
2.0 moldm\(^{-3}\)
- 0.25 moldm\(^{-3}\)
- 1.0 moldm\(^{-3}\)
- 0.5 moldm\(^{-3}\)
The correct answer is: A
Explanation
Given the Mass of the salt = 58.5g
Volume = 250 cm\(^3\) = 0.25 dm\(^3\)
Mass concentration = \(\frac{Mass}{Volume}\)
= \(\frac{58.5}{0.25}\) = 234 gdm\(^{-3}\)
Solubility (in moldm\(^{-3}\) = \(\frac{234}{111} \)
= 2.11 moldm\(^{-3}\)
\(\approxeq\) 2.0 moldm\(^{-3}\)
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