The electronic configuration of element Z is 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion.
- Z\(_3\)(SO\(_4\))\(_2\)
- ZSO\(_4\)
- Z\(_2\) SO\(_4\)
-
Z\(_2\)(SO\(_4\))\(_3\)
The correct answer is: D
Explanation
Z = 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\)
\(\therefore\) We have Z\(^{3+}\) and SO\(_4 ^{2-}\)
The reaction : Z\(^{3+}\) + SO\(_4 ^{2-}\) \(\to\) Z\(_2\)(SO\(_4\))\(_3\).
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