Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)
What will be the effect of decrease in temperature on the reaction?
-
Rate of backward reaction will increase
- The equilibrium constant will shift
- Rates of forward and backward reactions are not affected
- Rate of forward reaction will increase
The correct answer is: A
Explanation
The given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.
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