The oxidation state(s) of nitrogen in ammonium nitrite is/are
-
-3, +3
- +5
- -3, +5
- -3
The correct answer is: A
Explanation
Ammonium nitrite = NH\(_4\)NO\(_2\)
NH\(_4 ^+\): Let the oxidation number of Nitrogen = x
x + 4 = 1 \(\implies\) x = 1 - 4
x = -3
NO\(_2 ^-\): x - 4 = -1
x = -1 + 4 \(\implies\) x = +3.
The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.
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