An element Z contains 80% of \(^{16} _8\)Z and 20% of \(^{18} _8\)Z. Its relative atomic mass is
- 16.2
- 17.6
- 16.0
-
16.4
The correct answer is: D
Explanation
R.A.M of Z = \(16(\frac{80}{100}) + 18(\frac{20}{100})\)
= \(12.8 + 3.6\)
= 16.4
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