8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?
- 3.7dm\(^3\)
-
11.2dm\(^3\)
- 22.4dm\(^3\)
- 33dm\(^3\)
The correct answer is: B
Explanation
Molar mass of methane = 16g/mol
At S.T.P. its 8g occupies 11.2
so 16g occupies 22.4 dm\(^3\)
Molar mass of propane = 44g/mol\(^-1\) occupies 22.4dm\(^3\) at S.T.P
so 22g will occupy 11.2dm\(^3\)
There is an explanation video available .