The volume occupied by 1.58g of a gas at S.T.P is 500cm\(^3\). What is the relative molecular mass of the gas? [ G.M.V at S.T.P = 22.4dm\(^{3}\) ]
- 28
- 32
- 44
-
71
The correct answer is: D
Explanation
500cm\(^3\) of the gas weighed 1.58
: 22400cm\(^3\) of the gas weight
[22400 X 1.58g] ÷ [ 500 ]
= 71
There is an explanation video available .