At a given temperature and pressure, a gas X diffuses twice as fast as gas Y. It follows that
- Gas Y is two times as heavy as Gas X
-
Gas Y is four times as heavy as Gas X
- Gas Y is monoatomic
- Gas X is diatomic
The correct answer is: B
Explanation
The question can be explained by Graham's law of diffusion. According to this law, under the same conditions of temperature and pressure, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
\(\frac{R_x}{R_y}\) = \(\sqrt{\frac{M_y}{M_x}}\)
From the question, Gas X diffuses twice as fast as gas Y i.e x = 2y
This implies x =2 while y = 1
From \(\frac{R_x}{R_y}\) = \(\sqrt{\frac{M_y}{M_x}}\)
\(\frac{2}{1}\) = \(\sqrt{\frac{M_y}{M_x}}\)
\(\frac{4}{1}\) = \(\frac{M_y}{M_x}\)
M\(_y\) = 4 M\(_x\)
⇒ Gas Y is 4 times as heavy as Gas X. - Option B
There is an explanation video available .