127g of sodium chloride was dissolved in 1.0dm\(^3\) of distilled water at 25\(^0\)C . Determine the solubility in moldm\(^{-3}\) of sodium chloride at that temperature. [Na = 23, Cl = 35.5]
- 1.0
- 2.0
-
2.2
- 4.1
The correct answer is: C
Explanation
Solubility = Amount of solute dissolved in 1dm\(^3\) of solvent divided by the volume of solvent
Solubility = \(\frac{mass}{molar mass}\) x 1 dm\(^3\)
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Solubility = \(\frac{127}{58.5}\) x 1 dm\(^3\)
= 2.17
= 2.2 moldm\(^{-3}\)
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