When Sulphur(IV)oxide is passed into solution of acidified tetraoxomanganate(VII), the colour changes from
- blue to green
- pink to yellow
-
purple to colourless
- Orange to green
The correct answer is: C
Explanation
When sulphur dioxide (SO\(_2\) gas is passed through an acidified potassium permanganate (KMnO\(_4\)) solution, the solution changes from purple to colourless. This is because of a redox reaction, where KMnO\(_4\) acts as an oxidizing agent and SO\(_2\) acts as a reducing agent.
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