The molecular formular of a hydrocarbon with an empirical formula of CH\(_3\) and a molar mass of 30 is
- C\(_2\)H\(_4\)
- C\(_3\)H\(_3\)
-
C\(_2\)H\(_6\)
- C\(_6\)H\(_6\)
The correct answer is: C
Explanation
Empirical formula x n = Molecular mass
(CH\(_3\) ) X n = 30 ; Given that C = 12, H = 1
[ 12 + (1x3) ] n = 30
15n = 30
n = \(\frac{30}{15}\)
n = 2.
Molecular formula = (CH\(_3\) ) X n = (CH\(_3\) ) X 2 = C\(_2\)H\(_6\)
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