Determine the half-life of a first order reaction with constant 4.5 x 10\(^{-3}\) sec\(^{-1}\).

Explanation

The half-life of a first-order reaction can be calculated using the formula t\(\frac{1}{2}\) = \(\frac{0.693}{k}\)

Where t\(\frac{1}{2}\) = the half-life and k = the rate constant

From the question, we were given the value for k, which is the constant to be  4.5 x 10\(^{-3}\) sec\(^{-1}\)

t\(\frac{1}{2}\) = \(\frac{0.693}{k}\)  = \(\frac{0.693}{4.5 x 10\(^{-3}\)}\)

  t\(\frac{1}{2}\)      = 154 s

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