Determine the empirical formula of an oxide of sulphur containing 60% of oxygen
[S = 32, O = 16 ]
-
SO\(_3\)
- SO\(_2\)
- SO\(_4\)
- SO
The correct answer is: A
Explanation
Oxide of Sulphur means the compound formed is bonding between Sulphur and Oxygen.
Also, if the compound contains 60% Oxygen, then it must contain 40% Sulphur
Elements S O
%by mass of atoms 40 60
Divide by their masses \(\frac{40}{32}\) \(\frac{60}{16}\)
1.25 3.75
Divide through by smaller value \(\frac{1.25}{1.25}\) \(\frac{3.75}{1.25}\)
1 : 3
Empirical formula SO\(_3\)
There is an explanation video available .