If 11.0g of a gas occupies 5.6 dm\(^3\) at s.t.p., calculate its vapour density (1…

Explanation

  If  11.0g  occupies  5.6 dm\(^3\)

         x   will occupy 22.4 dm\(^3\)

    x = \(\frac{11\times 22.4}{5.6}\)

    x = 44g

But Molecular mass = 2 x  Vapour density

             44  = 2 x Vapour density

Vapour density =   \(\frac{44}{2}\) = 22

There is an explanation video available .