The hybridization scheme in ethyne is
-
sp
- sp\(^3\)
- sp\(^2\)d
- sp\(^2\)s
The correct answer is: A
Explanation
The hybridization scheme in ethyne is sp. In ethyne, each carbon atom's 2s orbital combines with one of its 2p orbitals to form two sp hybrid orbitals. The frontal lobes of these orbitals face away from each other, resulting in a straight line.
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