Calculate the number of moles of Copper that will be deposited, if 2 Faraday of electricity is passed through the copper during the electrolysis of copper(II)tetraoxosulphate(VI)
[1F = 96500C ]
- 0.5 mole
-
1.0 mole
- 2.0 moles
- 3.0 moles
The correct answer is: B
Explanation
NB: 1F = 1 mole of electrons of the atom of an element
In the case of copper (Cu), the valency is 2+.
⇒ Cu\(^{2+}\) + 2e\(^-\) → Cu
So, 2F = 1 mole of Cu
then, 2F = x mole
x = \(\frac{2\times1}{2}\)
x = 1 mole
There is an explanation video available .