The volume occupied by 1 mole of an ideal gas at a temperature of 13\(^0\)C and a pressure of 1.58 atm is
[ R = 0.082 atm dm\(^3\) K\(^{-1}\)mol\(^{-1}\) ]
-
14.84 dm\(^3\)
- 14.84 cm\(^3\)
- 0.64 dm\(^3\)
- 0.64 cm\(^3\)
The correct answer is: A
Explanation
According to the Ideal gas equation, PV = nRT
Given: P = 1.58 atm, V = ?, n = 1 mole, R = 0.082, T= 13 + 273K = 286K
Substituting all the given parameters,
V = \(\frac{nRT}{P}\)
V = \(\frac{1\times0.082\times286}{1.58}\)
V = 14.84 dm\(^3\)
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