The molar mass of a compound X is 56. its empirical formula is CH2. X is
-
butene.
- butyne.
- ethene.
- propene.
- propyne
The correct answer is: A
Explanation
\((CH_{2})x = 56\)
\((12 + 2)x = 56\)
\(14x = 56\)
\(x = \frac{56}{14}\)
\(x = 4\)
Hence, the empirical formula is \((CH_{2}) \times 4\)
= \(C_{4}H_{8}\)