The percentage composition of a hydrocarbon is 79.2 carbon 20.8 hydrogen. Calculate its empirical formula [H = 1, C = 12]
- CH
-
CH3
- CH4
- C2H2
- C2H6
The correct answer is: B
Explanation
Relative No of Moles for Carbon = 79.2% ÷ 12 = 6.6
Relative No of Moles for Hydrogen = 20.8% ÷ 1 = 20.8
Ratio of Moles = Carbon 6.6 ÷ 6.6 = 1 Hydrogen = 20.8 ÷ 6.6 ~ 3
EMPIRICAL FORMULA IS CH\(_3\)