C\(_6\)H\(_{12}\)O\(_6\)
What is the molar mass of the compound above?
[ H=1, C=12, O=16 }
- 45
- 61
-
180
- 123
- 244
The correct answer is: C
Explanation
The compound above is identified as glucose
Carbon - 12 \(\times\) 6 atoms present
Hydrogen - 1 \(\times\) 12 atoms present
Oxygen - 16 \(\times\) 6 atoms present
= 72 + 12 + 96
= 180