What quantity of copper will be deposited by the same quantity of electricity that deposited 9.0g of aluminum? (A = 27, Cu = 64)
- 64g
-
32g
- 7.1g
- 6.4g
- 3.2g
The correct answer is: B
Explanation
Al has valency of 3+:
3F will deposit 27g
xF will deposit 9g
cross multiply → \(\frac{9g * 3F}{27g}\)
: 1F = 9g
Cu has valency of 2+:
2F will deposit 64g
1F will deposit xg
cross multiply → \(\frac{64g * 1F}{2F}\)
: 1F = 32g