How many mole of AgNO\(_3\) are there in 500cm\(^3\) of 0.01M AgNO\(_3\) solution?

Explanation

Given:

V = 500 cm\(^3\)

C = 0.01M

n = ?

The relationship among the three parameters is  n = \(\frac{CV}{1000}\)

                                                                              n = \(\frac{0.01\times 500}{1000}\)

                                                                              n = 0.005 mole