An organic compound which reacts readily with bromine to form a compound with the formula CH3CHBrCH2Br is
- ethene
- propane
- butane
-
propene
- propyne
The correct answer is: D
Explanation
X + \(Br_2\) → \(CH_3CHBrCH_2Br\)
The compound must be propene because it is unsaturated and does react with bromine water to form 1,2, - dibromo- propane, unlike propyne, which will give a different product.