Mg\(_2\) + 2HCI\(_{(aq)}\) → MgCI\(_{2(g)}\) + H\(_{2(g)}\).
From the equation above what mass of hydrogen would be produced if 12.0 g of magnesium reacted completely with dilute hydrochloric acid? (H = 1, Mg = 24)
-
1.0g
- 2.0g
- 6.0g
- 12.0g
- 24.0g
The correct answer is: A
Explanation
Mg\(_2\) + 2HCI\(_{(aq)}\) → MgCI\(_{2(g)}\) + H\(_{2(g)}\).
24g Mg reacts with 2g H
1g Mg = \(\frac{2}{24}\)g H
12g Mg = \(\frac{2}{24} \times 12\)g H
= 1g H.