What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2…

Chemistry WAEC 1997

What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2 according to the following equation? C(s) + O2(g) → CO2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm3 at s.t.p]

  • 0.224dm3
  • 2.24dm3 checkmark
  • 4.40dm3
  • 4.48dm3
  • 22.4dm3

The correct answer is: B

Explanation

From the equation, C + O2 → CO2 : 22.dm3 of oxygen is required to form 44g of CO2 the volume of O2 required to produce 4.4gm is x, :. x = 44/44 X 22.4dm3
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