What is the effect of using vanadium (V) oxide as catalyst in the reaction represented by the following equation? 2SO2 + O2 ⇌ 2SO3; ∆H = – xKJmol-1
- Decreases the value of ∆H
- Increases the collision rate of reactant particles
- Shifts equilibrium position to the right
-
Reduces the time for attainment of equilibrium
The correct answer is: D
Explanation
In the contact process above; a temperature of about 500ºC and use of Vanadium(V)Oxide catalyst increase the reaction rate and enable equilibrium to be reached in a shorter time.