A feasible cell was constructed by joining the two half cells below. Cu2+ (aq) + 2e- → Cu(s) Eo = +0.34 V; Zn\({^2+}\) + 2e\(^-\) → Zn\((_s)\) Eo = – 0.76V. What is the standard e.m.f. of the cell?
- - 1.1V
- - 0.42V
- +0.42V
-
+1.1V
The correct answer is: D
Explanation
e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V