Calculate the mass of chlorine gas which occupies a volume of 1.12 dm\(^3\) a volume of 1.12 dm\(^3\) at s.t.p [Cl = 35.5, 1 mole og gas occupies 22.4 dm\(^3\) at s. t. p ]
- 1.80g
-
3.55g
- 7.10g
- 15.50g
The correct answer is: B
Explanation
1 mole Cl\(_2\) occupy 22.4dm\(^3\)
i.e 2 x 35.5 → 22.4 ; x → 1. 12
:. x = \(\frac{1.12}{22.4}\) x 2 x 35.5 = 3.55