Determine the mass of sulphur (IV) oxide obtained when 91.0g of oxygen reacts completely with sulphur according to the following equation: S(s) + O\(_2\)(g) → SO\(_2\)(g) [S = 32; O = 16]
- 123g
- 139g
- 155g
-
182g
The correct answer is: D
Explanation
S + O\(_2\) → SO\(_2\).
According to the equation 32g of O\(_2\) produced 64g of SO\(_2\)
therefore 91g of O2 will produce yg of SO2
y = \(\frac{91 * 64}{32}\)
y = 182g of SO\(_2\)