Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]
- 0.0156 g
- 0.625 g
- 1.00 g
-
25.0 g
The correct answer is: D
Explanation
1 mole of NaOH per dm3 has a mass of 40g.mass of NaOH in 0.125mole
= 0.125 x 40 = 5g.
mass in 5.00 dm3 of the solution.
= 5 x 5 = 25.0g.