The electronic configuration of an element is 1\(s^2\) 2\(s^2\) 2\(p^6\) 3\(s^2\) 3\(p^3\). Where is the element located in the periodic table?
- Group lll, period 3
- Group lll, period 5
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Group V, period 3
- Group V, period 5
The correct answer is: C
Explanation
the element belongs to group 5, since we have two coefficients that are the same we simply add the powers that give 5. while the highest coefficient gives the period that is 3.
therefore, the element is found in group 5 period 3.