An atom 23892X decays by alpha particle emission to give an atom Y. The atomic…

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Chemistry WAEC 2006

An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are

  • 90 and 234 respectively checkmark
  • 91 and 238 respectively
  • 92 and 236 respectively
  • 93 and 238 respectively

The correct answer is: A

Explanation

23892 X 234 90Y + 4 2 He Atomic number is 90 while mass number is 234
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