An atom 23892X decays by alpha particle emission to give an atom Y. The atomic…

Chemistry WAEC 2006

An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are

  • 90 and 234 respectively checkmark
  • 91 and 238 respectively
  • 92 and 236 respectively
  • 93 and 238 respectively

The correct answer is: A

Explanation

23892 X 234 90Y + 4 2 He Atomic number is 90 while mass number is 234
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